Факультет экономики и менеджмента. Кафедра прикладной математики и экономической кибернетики.
Отчет по учебной практике «Экономическая кибернетика»
Вариант 9
Задание 1.1
(3/5+0.425-0.005)/0.12/(30.5+1/6+10/3)
ans = 0.2500
Задание1. 2
а). 
;
(sin(5*pi/7+0.3*pi)^2-sin(5*pi/7-0.3*pi)^2)^1/3
ans = -3.090705145995175e-001
б). 
;
(sin(2.094395102393195e-001+3.839724354387525e+000)^2-sin(2.094395102393195e-001-3.839724354387525e+000)^2)^(1/3)
Ans = 7.3715e-001
Задание 1.3
a=5.3; b=10.6; c=876;
x1=(-b-sqrt(b^2-4*a*c))/2*a
x1 = -2.809000000000000e+001 -3.600377812119167e+002i
x2=(-b+sqrt(b^2-4*a*c))/2*a
x2 = -2.809000000000000e+001 +3.600377812119167e+002i
Задание 2
>> x=0.1:0.08:0.9
x =
Columns 1 through 6
1.0000e-001 1.8000e-001 2.6000e-001 3.4000e-001 4.2000e-001 5.0000e-001
Columns 7 through 11
5.8000e-001 6.6000e-001 7.4000e-001 8.2000e-001 9.0000e-001
>> A=2*x
A =
Columns 1 through 6
2.0000e-001 3.6000e-001 5.2000e-001 6.8000e-001 8.4000e-001 1.0000e+000
Columns 7 through 11
1.1600e+000 1.3200e+000 1.4800e+000 1.6400e+000 1.8000e+000
>> B=A+3
B =
Columns 1 through 6
3.2000e+000 3.3600e+000 3.5200e+000 3.6800e+000 3.8400e+000 4.0000e+000
Columns 7 through 11
4.1600e+000 4.3200e+000 4.4800e+000 4.6400e+000 4.8000e+000
>> C=sqrt(B)
C =
Columns 1 through 6
1.7889e+000 1.8330e+000 1.8762e+000 1.9183e+000 1.9596e+000 2.0000e+000
Columns 7 through 11
2.0396e+000 2.0785e+000 2.1166e+000 2.1541e+000 2.1909e+000
>> pow=x.^3
pow =
Columns 1 through 6
1.0000e-003 5.8320e-003 1.7576e-002 3.9304e-002 7.4088e-002 1.2500e-001
Columns 7 through 11
1.9511e-001 2.8750e-001 4.0522e-001 5.5137e-001 7.2900e-001
>> E=(pi/2)*pow
E =
Columns 1 through 6
1.5708e-003 9.1609e-003 2.7608e-002 6.1739e-002 1.1638e-001 1.9635e-001
Columns 7 through 11
3.0648e-001 4.5160e-001 6.3652e-001 8.6609e-001 1.1451e+000
>> F=tan(pi/2)*pow
F =
Columns 1 through 6
1.6331e+013 9.5244e+013 2.8704e+014 6.4188e+014 1.2099e+015 2.0414e+015
Columns 7 through 11
3.1864e+015 4.6952e+015 6.6178e+015 9.0045e+015 1.1905e+016
>> h=sqrt(B)*tan(pi/2)
h =
Columns 1 through 6
2.9214e+016 2.9936e+016 3.0640e+016 3.1329e+016 3.2003e+016 3.2662e+016
Columns 7 through 11
3.3309e+016 3.3944e+016 3.4567e+016 3.5179e+016 3.5780e+016
Задание 3
Введите матрицу(5*6). Постройте вектор, элементами которого являются средние арифметические наибольшего и наименьшего элементов соответствующей строки матрицы.
>> A=[1 2 3 4 5;3 7 3 9 4;2 7 3 9 5;1 6 9 0 4;4 7 2 5 7;2 8 4 6 5]
A =
1 2 3 4 5
3 7 3 9 4
2 7 3 9 5
1 6 9 0 4
4 7 2 5 7
2 8 4 6 5
>> size(A)
ans =
6 5
>> max(A)
ans =
4 8 9 9 7
>> min(A)
ans =
1 2 2 0 4
>> v1=[1+2+3+4+5]/5
v1 = 3
>> v2=[3+7+3+9+4]
v2 = 5.200000000000000e+000
>> v3=[2+7+3+9+5]
v3 =1.923076923076923e-001
>> v4=[1+6+9+0+4]
v4 = 4
>> v5=[4+7+2+5+7]
v5 = 5
>> v6=[2+8+4+6 +5]
v6 = 5
>> randn(5,6)
ans =
Columns 1 through 3
-4.325648115282207e-001 1.190915465642999e+000 -1.867085776814394e-001
-1.665584378238097e+000 1.189164201652103e+000 7.257905482933027e-001
1.253323064748307e-001 -3.763327659331765e-002 -5.883165430141887e-001
2.876764203585489e-001 3.272923614086541e-001 2.183185818197101e+000
-1.146471350681464e+000 1.746391428209245e-001 -1.363958830865957e-001
Columns 4 through 6
1.139313135208096e-001 2.944108163926404e-001 8.579966728282626e-001
1.066768211359189e+000 -1.336181857937804e+000 1.254001421602532e+000
5.928146052360535e-002 7.143245518189522e-001 -1.593729576447477e+000
-9.564840548366904e-002 1.623562064446271e+000 -1.440964431901020e+000
-8.323494636500225e-001 -6.917757017022868e-001 5.711476236581780e-001
